SQL Server 2016 имеет новую встроенную функцию STRING_SPLIT().
Предполагая создание встроенных функций, но функции CLR не разрешены:
CREATE FUNCTION dbo.WORD_SPLIT
(
@String AS nvarchar(4000)
)
RETURNS TABLE
AS
RETURN
(
WITH Spaces AS
(
SELECT Spaced.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY (SELECT 1)) AS ordinal
FROM STRING_SPLIT(@String, ' ') AS Spaced
)
, Tabs AS
(
SELECT Tabbed.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY s.ordinal, (SELECT 1)) AS ordinal
FROM Spaces AS s
CROSS APPLY STRING_SPLIT(s.[value], ' ') AS Tabbed
)
, NewLines1 AS
(
SELECT NewLined1.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY t.ordinal, (SELECT 1)) AS ordinal
FROM Tabs AS t
CROSS APPLY STRING_SPLIT(t.[value], CHAR(13)) AS NewLined1
)
, NewLines2 AS
(
SELECT NewLined2.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY nl1.ordinal, (SELECT 1)) AS ordinal
FROM NewLines1 AS nl1
CROSS APPLY STRING_SPLIT(nl1.[value], CHAR(10)) AS NewLined2
)
SELECT LTRIM(RTRIM(nl2.[value])) AS [value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY nl2.ordinal, (SELECT 1)) AS ordinal
FROM NewLines2 AS nl2
WHERE LTRIM(RTRIM(nl2.[value])) <> ''
)
GO
Использование:
-- Not Normailized
SELECT i.*, split.[value], split.[ordinal]
FROM @input AS i
CROSS APPLY dbo.WORD_SPLIT(i.teststring) AS split
-- Normalized
;WITH Splitted AS
(
SELECT split.[value], split.[ordinal]
FROM @input AS i
CROSS APPLY dbo.WORD_SPLIT(i.teststring) AS split
)
SELECT *
FROM (SELECT [value], 'part' + CONVERT(nvarchar(20), [ordinal]) AS [parts] FROM Splitted) AS s
PIVOT (MAX([value]) FOR [parts] IN ([part1], [part2], [part3], [part4])
Или предполагая, что для каждой безопасности вам не разрешено вносить изменения в схему:
WITH Splitting AS
(
SELECT teststring AS [value]
FROM @input
)
WITH Spaces AS
(
SELECT Spaced.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY (SELECT 1)) AS ordinal
FROM Splitting AS sp
CROSS APPLY STRING_SPLIT(sp.[value], ' ') AS Spaced
)
, Tabs AS
(
SELECT Tabbed.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY s.ordinal, (SELECT 1)) AS ordinal
FROM Spaces AS s
CROSS APPLY STRING_SPLIT(s.[value], ' ') AS Tabbed
)
, NewLines1 AS
(
SELECT NewLined1.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY t.ordinal, (SELECT 1)) AS ordinal
FROM Tabs AS t
CROSS APPLY STRING_SPLIT(t.[value], CHAR(13)) AS NewLined1
)
, NewLines2 AS
(
SELECT NewLined2.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY nl1.ordinal, (SELECT 1)) AS ordinal
FROM NewLines1 AS nl1
CROSS APPLY STRING_SPLIT(nl1.[value], CHAR(10)) AS NewLined2
)
, Splitted AS
(
SELECT LTRIM(RTRIM(nl2.[value])) AS [teststring], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY nl2.ordinal, (SELECT 1)) AS ordinal
FROM NewLines2 AS nl2
WHERE LTRIM(RTRIM(nl2.[value])) <> ''
)
SELECT *
FROM (SELECT [value], 'part' + CONVERT(nvarchar(20), [ordinal]) AS [parts] FROM Splitted) AS s
PIVOT (MAX([value]) FOR [parts] IN ([part1], [part2], [part3], [part4])
Надеюсь, полезно!
person
TamusJRoyce
schedule
22.08.2017
For security reason I cannot use functions.
что это значит?LEN()
иSUBSTRING
— это функции - person Panagiotis Kanavos   schedule 07.07.2016