Я использую pyspark==2.4.3 и просто хочу запустить файл hql.
use myDatabaseName;
show tables;
и вот что я пробовал
from os.path import expanduser, join, abspath
from pyspark.sql import SparkSession
from pyspark.sql import Row
# warehouse_location points to the default location for managed databases and tables
warehouse_location = abspath('spark-warehouse')
spark = SparkSession \
.builder \
.appName("Python Spark SQL Hive integration example") \
.config("spark.sql.warehouse.dir", warehouse_location) \
.enableHiveSupport() \
.getOrCreate()
with open('full/path/to/my/hqlfile') as t:
q=t.read()
print q
'use myDatabaseName;show tables;\n'
spark.sql(q)
но я получаю
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/some/path/python2.7/site-packages/pyspark/sql/session.py", line 767, in sql
return DataFrame(self._jsparkSession.sql(sqlQuery), self._wrapped)
File "/some/path/python2.7/site-packages/py4j/java_gateway.py", line 1257, in __call__
answer, self.gateway_client, self.target_id, self.name)
File "/some/path/python2.7/site-packages/pyspark/sql/utils.py", line 73, in deco
raise ParseException(s.split(': ', 1)[1], stackTrace)
pyspark.sql.utils.ParseException: u"\nmismatched input ';' expecting <EOF>(line 1, pos 11)\n\n== SQL ==\nuse myDatabaseName;show tables;\n-----------^^^\n"
Что я делаю не так ?